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The 'Indian Express' Mahesh Bhupathi and Leander Paes came ahead of a tough test in the third round of Australia Open after beating No. 14-seeded Spaniards Marcel Granollers and Tommy Robredo 6-4, 4-6, 6-4 on Monday Melbourne.
Third seeds that were recorded 41 winners, want to complete bristol the Grand Slam individually, as both have won the other three "majors". Together they reached the end of Melbourn in 1999 (p. Bjorkman-Rafter), while Bhupathi was also runner-up in 2009 (w / Knowles) and Paes fell in 2006 (c / Damm).
Bhupathi and Paes are perfect together again after 2011, which are playing a Grand Slam for the first time in nine years, since the first week of the season won the Aircel Chennai Open title.
In the quarterfinals Bhupathi and Paes will face eighth-seeded Michael Llodra and Nenad Zimonjic, bristol who imposed the 'India-Pakistan Express' of Rohan Bopanna and Aisam-Ul-Haq Qureshi 3-6, 7-6 (6), 7-6 (3) in two hours and 13 minutes. Frenchman Llodra and Serbian bristol Zimonjic are playing together for the second time in a tournament circuit and the first Grand Slam.
The fifth seeds Mariusz Fyrstenberg and Marcin Matkowski had to work to get into the round of the last eight after beating Australian special guests Colin Ebelthite and Adam Feeney 6-1, 4-6, 6-4. While Eric Butorac and Jean-Julien Rojer crushed bristol the Spaniards David Marrero and Ruben Ramirez Hidalgo.
Jumping Stan was the greatest of the decade Wawrinka had a busy reception Mental Game: The strategy Stan Wawrinka won his first Grand Slam in Melbourne celebrates the triumph of Twitter # Stanimal The numbers behind victory Wawrinka
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